X^2-2450x+1.501=0

Solution for X^2-2450x+1.501=0 equation:

X^2-2450X+1.501=0

a = 1; b = -2450; c = +1.501;
Δ = b2-4ac
Δ = -24502-4·1·1.501
Δ = 6002493.996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2450)-\sqrt{6002493.996}}{2*1}=\frac{2450-\sqrt{6002493.996}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2450)+\sqrt{6002493.996}}{2*1}=\frac{2450+\sqrt{6002493.996}}{2}
$